{"id":57,"date":"2021-11-09T07:47:00","date_gmt":"2021-11-09T07:47:00","guid":{"rendered":"http:\/\/45.41.235.130\/~onlined1\/blog\/?p=57"},"modified":"2021-11-23T07:47:46","modified_gmt":"2021-11-23T07:47:46","slug":"dice-probabilities-part-3","status":"publish","type":"post","link":"https:\/\/www.online-dice.com\/blog\/dice-probabilities-part-3\/","title":{"rendered":"Dice Probabilities \u2013 Part 3"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">You may be wondering: What is my chance of rolling all the values on \u201cn\u201d dice equal to or higher than some number \u201cy\u201d?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This problems is very similar to our problem in part 2, but this time \u201cp\u201d is not simply equal to 1\/s, but instead it is equal to 1\/s multiplied by all the possibilities that fulfil the initial condition (in this case, being equal or higher than some number \u201cy\u201d).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">For example, let\u2019s imagine that we have a 6-sided die and y = 3. This means that we wish to roll anything above or equal to 3, i.e. a 6, 5, 4, or 3 with a single 6-sided die.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The probability p is then 4 possible outcomes that satisfy my condition p(c) multiplied by 1\/s, i.e. p = p(c) * 1\/s = 4 * 1\/6 = 2\/3 = 66.67%.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">If we had several dice instead of just a single one, we must use the same rule as in part 2, and multiply p by itself by the number of dice n. Therefore the formula becomes: P = (p(c) * 1\/s)\u207f<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">With this you can, for example, calculate the probability of rolling only numbers equal or above 4 with three 10-sided dice:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">P = (p(c) * 1\/s)\u207f = (7 * 1\/10)\u00b3 = (7\/10)\u00b3 = 34.3%<\/p>\n","protected":false},"excerpt":{"rendered":"<p>You may be wondering: What is my chance of rolling all the values on \u201cn\u201d dice equal to or higher than some number \u201cy\u201d?<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2],"tags":[],"class_list":["post-57","post","type-post","status-publish","format-standard","hentry","category-dice-probabilities","entry"],"_links":{"self":[{"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/posts\/57","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/comments?post=57"}],"version-history":[{"count":1,"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/posts\/57\/revisions"}],"predecessor-version":[{"id":58,"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/posts\/57\/revisions\/58"}],"wp:attachment":[{"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/media?parent=57"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/categories?post=57"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.online-dice.com\/blog\/wp-json\/wp\/v2\/tags?post=57"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}